\(\int \frac {(1-2 x)^3}{(2+3 x)^5 (3+5 x)^2} \, dx\) [1414]

Optimal result

Integrand size = 22, antiderivative size = 68 \[ \int \frac {(1-2 x)^3}{(2+3 x)^5 (3+5 x)^2} \, dx=-\frac {343}{36 (2+3 x)^4}-\frac {3136}{27 (2+3 x)^3}-\frac {2541}{2 (2+3 x)^2}-\frac {16698}{2+3 x}-\frac {6655}{3+5 x}+103455 \log (2+3 x)-103455 \log (3+5 x) \]

[Out]

-343/36/(2+3*x)^4-3136/27/(2+3*x)^3-2541/2/(2+3*x)^2-16698/(2+3*x)-6655/(3+5*x)+103455*ln(2+3*x)-103455*ln(3+5
*x)

Rubi [A] (verified)

Time = 0.02 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {90} \[ \int \frac {(1-2 x)^3}{(2+3 x)^5 (3+5 x)^2} \, dx=-\frac {16698}{3 x+2}-\frac {6655}{5 x+3}-\frac {2541}{2 (3 x+2)^2}-\frac {3136}{27 (3 x+2)^3}-\frac {343}{36 (3 x+2)^4}+103455 \log (3 x+2)-103455 \log (5 x+3) \]

[In]

Int[(1 - 2*x)^3/((2 + 3*x)^5*(3 + 5*x)^2),x]

[Out]

-343/(36*(2 + 3*x)^4) - 3136/(27*(2 + 3*x)^3) - 2541/(2*(2 + 3*x)^2) - 16698/(2 + 3*x) - 6655/(3 + 5*x) + 1034
55*Log[2 + 3*x] - 103455*Log[3 + 5*x]

Rule 90

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {343}{3 (2+3 x)^5}+\frac {3136}{3 (2+3 x)^4}+\frac {7623}{(2+3 x)^3}+\frac {50094}{(2+3 x)^2}+\frac {310365}{2+3 x}+\frac {33275}{(3+5 x)^2}-\frac {517275}{3+5 x}\right ) \, dx \\ & = -\frac {343}{36 (2+3 x)^4}-\frac {3136}{27 (2+3 x)^3}-\frac {2541}{2 (2+3 x)^2}-\frac {16698}{2+3 x}-\frac {6655}{3+5 x}+103455 \log (2+3 x)-103455 \log (3+5 x) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.03 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.03 \[ \int \frac {(1-2 x)^3}{(2+3 x)^5 (3+5 x)^2} \, dx=-\frac {343}{36 (2+3 x)^4}-\frac {3136}{27 (2+3 x)^3}-\frac {2541}{2 (2+3 x)^2}-\frac {16698}{2+3 x}-\frac {6655}{3+5 x}+103455 \log (5 (2+3 x))-103455 \log (3+5 x) \]

[In]

Integrate[(1 - 2*x)^3/((2 + 3*x)^5*(3 + 5*x)^2),x]

[Out]

-343/(36*(2 + 3*x)^4) - 3136/(27*(2 + 3*x)^3) - 2541/(2*(2 + 3*x)^2) - 16698/(2 + 3*x) - 6655/(3 + 5*x) + 1034
55*Log[5*(2 + 3*x)] - 103455*Log[3 + 5*x]

Maple [A] (verified)

Time = 2.46 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.78

method	result	size
norman	\(\frac {-2793285 x^{4}-\frac {343827337}{108} x -\frac {130688491}{18} x^{2}-\frac {14711301}{2} x^{3}-\frac {18835325}{36}}{\left (2+3 x \right )^{4} \left (3+5 x \right )}+103455 \ln \left (2+3 x \right )-103455 \ln \left (3+5 x \right )\)	\(53\)
risch	\(\frac {-2793285 x^{4}-\frac {343827337}{108} x -\frac {130688491}{18} x^{2}-\frac {14711301}{2} x^{3}-\frac {18835325}{36}}{\left (2+3 x \right )^{4} \left (3+5 x \right )}+103455 \ln \left (2+3 x \right )-103455 \ln \left (3+5 x \right )\)	\(54\)
default	\(-\frac {343}{36 \left (2+3 x \right )^{4}}-\frac {3136}{27 \left (2+3 x \right )^{3}}-\frac {2541}{2 \left (2+3 x \right )^{2}}-\frac {16698}{2+3 x}-\frac {6655}{3+5 x}+103455 \ln \left (2+3 x \right )-103455 \ln \left (3+5 x \right )\)	\(63\)
parallelrisch	\(\frac {8044660800 \ln \left (\frac {2}{3}+x \right ) x^{5}-8044660800 \ln \left (x +\frac {3}{5}\right ) x^{5}[phone] \ln \left (\frac {2}{3}+x \right ) x^{4}-26279225280 \ln \left (x +\frac {3}{5}\right ) x^{4}[phone] x^{5}[phone] \ln \left (\frac {2}{3}+x \right ) x^{3}-34323886080 \ln \left (x +\frac {3}{5}\right ) x^{3}[phone] x^{4}[phone] \ln \left (\frac {2}{3}+x \right ) x^{2}-22405870080 \ln \left (x +\frac {3}{5}\right ) x^{2}[phone] x^{3}[phone] \ln \left (\frac {2}{3}+x \right ) x -7309716480 \ln \left (x +\frac {3}{5}\right ) x [phone] x^{2}[phone] \ln \left (\frac {2}{3}+x \right )-953441280 \ln \left (x +\frac {3}{5}\right )[phone] x}{192 \left (2+3 x \right )^{4} \left (3+5 x \right )}\)	\(139\)

[In]

int((1-2*x)^3/(2+3*x)^5/(3+5*x)^2,x,method=_RETURNVERBOSE)

[Out]

(-2793285*x^4-343827337/108*x-130688491/18*x^2-14711301/2*x^3-18835325/36)/(2+3*x)^4/(3+5*x)+103455*ln(2+3*x)-
103455*ln(3+5*x)

Fricas [A] (verification not implemented)

none

Time = 0.22 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.69 \[ \int \frac {(1-2 x)^3}{(2+3 x)^5 (3+5 x)^2} \, dx=-\frac {301674780 \, x^{4} + 794410254 \, x^{3} + 784130946 \, x^{2} + 11173140 \, {\left (405 \, x^{5} + 1323 \, x^{4} + 1728 \, x^{3} + 1128 \, x^{2} + 368 \, x + 48\right )} \log \left (5 \, x + 3\right ) - 11173140 \, {\left (405 \, x^{5} + 1323 \, x^{4} + 1728 \, x^{3} + 1128 \, x^{2} + 368 \, x + 48\right )} \log \left (3 \, x + 2\right ) + 343827337 \, x + 56505975}{108 \, {\left (405 \, x^{5} + 1323 \, x^{4} + 1728 \, x^{3} + 1128 \, x^{2} + 368 \, x + 48\right )}} \]

[In]

integrate((1-2*x)^3/(2+3*x)^5/(3+5*x)^2,x, algorithm="fricas")

[Out]

-1/108*(301674780*x^4 + 794410254*x^3 + 784130946*x^2 + 11173140*(405*x^5 + 1323*x^4 + 1728*x^3 + 1128*x^2 + 3
68*x + 48)*log(5*x + 3) - 11173140*(405*x^5 + 1323*x^4 + 1728*x^3 + 1128*x^2 + 368*x + 48)*log(3*x + 2) + 3438
27337*x + 56505975)/(405*x^5 + 1323*x^4 + 1728*x^3 + 1128*x^2 + 368*x + 48)

Sympy [A] (verification not implemented)

Time = 0.08 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.90 \[ \int \frac {(1-2 x)^3}{(2+3 x)^5 (3+5 x)^2} \, dx=- \frac {301674780 x^{4} + 794410254 x^{3} + 784130946 x^{2} + 343827337 x + 56505975}{43740 x^{5} + 142884 x^{4} + 186624 x^{3} + 121824 x^{2} + 39744 x + 5184} - 103455 \log {\left (x + \frac {3}{5} \right )} + 103455 \log {\left (x + \frac {2}{3} \right )} \]

[In]

integrate((1-2*x)**3/(2+3*x)**5/(3+5*x)**2,x)

[Out]

-(301674780*x**4 + 794410254*x**3 + 784130946*x**2 + 343827337*x + 56505975)/(43740*x**5 + 142884*x**4 + 18662
4*x**3 + 121824*x**2 + 39744*x + 5184) - 103455*log(x + 3/5) + 103455*log(x + 2/3)

Maxima [A] (verification not implemented)

none

Time = 0.21 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.97 \[ \int \frac {(1-2 x)^3}{(2+3 x)^5 (3+5 x)^2} \, dx=-\frac {301674780 \, x^{4} + 794410254 \, x^{3} + 784130946 \, x^{2} + 343827337 \, x + 56505975}{108 \, {\left (405 \, x^{5} + 1323 \, x^{4} + 1728 \, x^{3} + 1128 \, x^{2} + 368 \, x + 48\right )}} - 103455 \, \log \left (5 \, x + 3\right ) + 103455 \, \log \left (3 \, x + 2\right ) \]

[In]

integrate((1-2*x)^3/(2+3*x)^5/(3+5*x)^2,x, algorithm="maxima")

[Out]

-1/108*(301674780*x^4 + 794410254*x^3 + 784130946*x^2 + 343827337*x + 56505975)/(405*x^5 + 1323*x^4 + 1728*x^3
+ 1128*x^2 + 368*x + 48) - 103455*log(5*x + 3) + 103455*log(3*x + 2)

Giac [A] (verification not implemented)

none

Time = 0.31 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.99 \[ \int \frac {(1-2 x)^3}{(2+3 x)^5 (3+5 x)^2} \, dx=-\frac {6655}{5 \, x + 3} + \frac {5 \, {\left (\frac {9923332}{5 \, x + 3} + \frac {3831284}{{\left (5 \, x + 3\right )}^{2}} + \frac {514536}{{\left (5 \, x + 3\right )}^{3}} + 8795037\right )}}{4 \, {\left (\frac {1}{5 \, x + 3} + 3\right )}^{4}} + 103455 \, \log \left ({\left | -\frac {1}{5 \, x + 3} - 3 \right |}\right ) \]

[In]

integrate((1-2*x)^3/(2+3*x)^5/(3+5*x)^2,x, algorithm="giac")

[Out]

-6655/(5*x + 3) + 5/4*(9923332/(5*x + 3) + 3831284/(5*x + 3)^2 + 514536/(5*x + 3)^3 + 8795037)/(1/(5*x + 3) +
3)^4 + 103455*log(abs(-1/(5*x + 3) - 3))

Mupad [B] (verification not implemented)

Time = 1.26 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.82 \[ \int \frac {(1-2 x)^3}{(2+3 x)^5 (3+5 x)^2} \, dx=206910\,\mathrm {atanh}\left (30\,x+19\right )-\frac {6897\,x^4+\frac {181621\,x^3}{10}+\frac {130688491\,x^2}{7290}+\frac {343827337\,x}{43740}+\frac {3767065}{2916}}{x^5+\frac {49\,x^4}{15}+\frac {64\,x^3}{15}+\frac {376\,x^2}{135}+\frac {368\,x}{405}+\frac {16}{135}} \]

[In]

int(-(2*x - 1)^3/((3*x + 2)^5*(5*x + 3)^2),x)

[Out]

206910*atanh(30*x + 19) - ((343827337*x)/43740 + (130688491*x^2)/7290 + (181621*x^3)/10 + 6897*x^4 + 3767065/2
916)/((368*x)/405 + (376*x^2)/135 + (64*x^3)/15 + (49*x^4)/15 + x^5 + 16/135)